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5x^2+70x=552
We move all terms to the left:
5x^2+70x-(552)=0
a = 5; b = 70; c = -552;
Δ = b2-4ac
Δ = 702-4·5·(-552)
Δ = 15940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15940}=\sqrt{4*3985}=\sqrt{4}*\sqrt{3985}=2\sqrt{3985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{3985}}{2*5}=\frac{-70-2\sqrt{3985}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{3985}}{2*5}=\frac{-70+2\sqrt{3985}}{10} $
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